Question

what is the perpendicular distance of a point (2,3) from the line 2x-4y +3=0​

Answer 1

Step-by-step explanation:

dont make as brainlest just check whetere it is correct or not

Answer 2

Answer:

$\huge\boxed{\dfrac{5\sqrt{13}}{13}}$

Step-by-step explanation:

The formula:

$(x_o;\ y_o);\ Ax+By+C=0\\\\d=\dfrac{|Ax_o+By_o+C|}{\sqrt{A^2+B^2}}$

We have

$(2,\ 3)\to x_o=2;\ y_o=3\\\\2x-4y+3=0\to A=2;\ B=-4;\ C=3$

Substitute

$d=\dfrac{|(2)(2)+(-4)(3)+3|}{\sqrt{2^2+3^2}}=\dfrac{|4-12+3|}{\sqrt{4+9}}=\dfrac{|-5|}{\sqrt{13}}=\dfrac{5}{\sqrt{13}}\cdot\dfrac{\sqrt{13}}{\sqrt{13}}=\dfrac{5\sqrt{13}}{13}$