What is the perpendicular distance of point p (− 9, − 7) from x axis and – y axis? Give reason to support your answer
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Step-by-step explanation:
The perpendicular distance of the point (4,3) from x-axis.
The point where the line drawn from (4,3) is perpendicular to x-axis is (4,0).
[ Just below the (4,3), the x-coordinate remains same but y-coordinate gets zero.]
Now, the vertical distance between (4,3) and (4,0) = \sqrt{(4-4)^2+(3-0)^2}
\sqrt{(3)^2}=3 units.
Hence, the perpendicular distance of the point (4,3) from x-axis= 3 units.
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