Question

what is the PH of 0.001M acetic acid..... pLz answer with correct explanation...

Answer 1

Answer:

3

Explanation:

CH3COOH<=>CH3COO(anion)+H(cation)

[H]=0.001=1/10³

pH=-log[H]

= -log1/10³

=-(-3)

=3

Answer 2

Answer:

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what is the pH of 0.001.....

hope this helps u