Question

what is the pH of 0.003n NaOH solution
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Answer 1

Answer:

See, as pH is nothing but negative logarithm of concentration of H+ ion. NaOH is a base and a strong electrolyte (a strong electrolyte is a one which dissociates completely) so it completely dissociates into Na+ ion and OH- ion . As we are provided with 0.0001 N NaOH first we have to find its molarity and the relation between the two is :

Normality = molarity * n factor (n factor for the bases is equal to their acidity or the number of replacable OH- ion per molecule of the base ) here n=1 so normality is equal to molarity so we are having 0.0001 M Na0H which dissociates completely to give 0.0001 M Na+ ion and 0.0001 M OH- ion . We will use OH- ion concentration (0.0001) to calculate pOH(negative log of OH- ion concentration )

We get pOH= - log (10^-4) = 4

We know pH + pOH =14 so pH =14–4 = 10

So,pH of 0.0001N. NaOH solution is 10 (alkaline ) .

Explanation: