Question

What is the ph of 0.01 m h2s solution k1 is equal to 9 into 10 to the power minus 8 is equal to 1.2 into 10 to the power minus 30?

Answer 1

Answer:

Here we see that , K2 is much smaller than K1and so,it is expected that [H3O+]− hydronium ion is formed in first dissociation as : H2S+H2O→H3O++ HS .

Answer 2

Explanation:

Here we see that , K2K2 is much smaller than K1K1and so,it is expected that [H3O+]−[H3O+]− hydronium ion is formed in first dissociation as :

H2S+H2O→H3O++HS−H2S+H2O→H3O++HS−

So, K1=[H3O+][HS]/[H2S]K1=[H3O+][HS]/[H2S]

Or K1=[H3O+]2/[H2S]K1=[H3O+]2/[H2S]

[H3O+]=(√K1.[H2S])[H3O+]=(K1.[H2S])

=(√1.0×10−7×0.1)=1.0×10−4=(1.0×10−7×0.1)=1.0×10−4

Now, pH=−log[H3O+]=−log[1.0×10−4]=4