Question

What is the ph of 0.01m h2s solution also determine?

Answer 1

Hey mate,

● Answer-
pH = 4.5

● Explaination-
# Given-
Kc = 10^-7

# Solution-
In aq.H2S soln, its dissociation is given by-
H2S + H2O ---> H3O+ + HS+
m m 0 0
m-x m-x x x

Equilibrium constant is -
Kc = [H30+][HS-] / [H2S]
Kc = [H30+]^2 / [H2S]
10^-7 = [H3O+]^2 / 0.01
[H3O+] = √(10^-9)
[H3O+] = 3.16×10^-5 ions

pH of the solution is -
pH = -log(3.16×10^-5)
pH = 4.5

Hope this is helpful.