Chemistry, asked by anikrahulgupta4497, 1 month ago

What is the pH of 0.05 m baoh2?

Answers

Answered by iAmHoBiSpRiTexD

1

Explanation:

Ba(OH)2 ⟶Ba + 2 +2OH −

∴[OH − ] = 0.05 × 2 = 0.10M

⇒pOH = −log(0.10) = 1

As we know that,

pH + pOH = 14

∴pH=14−pOH=14−1=13

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