What is the pH of 0.060 M NH4Cl?
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Answer: For the salt of strong acid and weak base
H
+
=
K
b
K
w
×C
[H
+
]=
10
−5
10
−14
×2×10
−2
−log[H
+
]=6−
2
1
log20
∴pH=5.35.
Explanation:
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