what is the pH of 0.1 M of solution of a base whose KB is equal to 1 into 10 to the power minus 5
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answer of this question is 11
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The hydroxide ion Conc. [OH-] =√(Kb x C)
=[OH-]=√(10^-5 x 0.1)= 10^-3 So pOH=- log(10^-3)= 3
So pH= 14- pOH
= 14- 3
= 11
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