what is the ph of 1M Nacl at 298 K?
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3
+7 is the answer for this question
MdAwais:
solve full bro
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thus.,answer is ph value is 7
because 298k= 24.85°c=approx 25°c
The time when we add NaCl into water, it will completely dissociate into Na+ and Cl- ions ( salt hydrolysis ).
Parallelly water will build up it's own equilibrium
H2O → OH- + H+ K = 10^(-14 ) at 25℃
Na+ will combine with OH- whereas Cl- will combine with H+ , but as NaOH and HCl are strong base and acid simultaneously ,they will immediately dissociates into its ionic form completely
So in medium, we will have equal concentration of H+ = OH-
As per experimental data
Dissociation constant of water at 25 ℃ is
10^ (-14)= [H+] [OH-]
So at 25℃ [ H+]= [OH-] =10^(-7 )
Thus PH comes 7 at 25℃
because 298k= 24.85°c=approx 25°c
The time when we add NaCl into water, it will completely dissociate into Na+ and Cl- ions ( salt hydrolysis ).
Parallelly water will build up it's own equilibrium
H2O → OH- + H+ K = 10^(-14 ) at 25℃
Na+ will combine with OH- whereas Cl- will combine with H+ , but as NaOH and HCl are strong base and acid simultaneously ,they will immediately dissociates into its ionic form completely
So in medium, we will have equal concentration of H+ = OH-
As per experimental data
Dissociation constant of water at 25 ℃ is
10^ (-14)= [H+] [OH-]
So at 25℃ [ H+]= [OH-] =10^(-7 )
Thus PH comes 7 at 25℃
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