Question

what is the pH of 2*10^-8 M H2so4​

Answer 1

Answer:

Here we can't directly take the -log[H+] as H2SO4 is not the only acid here, water is also undergoing auto protolysis and it's concentration of [H+] is 10^(-7) which is in fact more than what H2SO4 is contributing.

So net [H+] is =10^(-7) +2*(10^(-8))

On simplifying we get 12*10^(-8)

So pH=-log(12*10^(-8)) = 6.92 (approx.)

Explanation:

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