Chemistry, asked by sangk5084, 1 year ago

What is the pH of a 0.40M ammonia solution

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Answered by Michelshyla

2

· Kb = 10^-4.74 = 1.8 x 10^-5. NH3 + H2O <=> NH4+ + OH- 1.8 x 10^-5 =x^2 / 0.40-x x = [OH-]= 0.00268 M pOH = 2.57

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