What is the ph of a saturated solution of cu(oh)2 (ksp = 2.6 x 10-19)?
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1
Answer:
7.90
Explanation:
Cu(OH)
2
⇌Cu
2+
+2OH¯
Ksp=[Cu
2+
][OH¯]
2
1.6×10
−19
=(s)(2s)
2
=4s
3
After dividing by 4 and then taking the cube root:
S=3.42×10
−7
M
[OH¯].That value is '2s.'
[OH¯]=6.84×10
−7
M
pOH=−log6.84×10
−7
=6.165
pH=14−6.165=7.835
Hence the pH value is7.835≈7.9
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