Question

What is the pH of a solution with [H₂O]= 1.0 × 10-⁸ M? what is the pOH of solution?​

Answer 1

Answer:

6.98

Explanation:

[H+] total =[H+] acid +[H+] water

Since, HCl is a strong acid and is completely ionized

[H+]HCl=1.0×10−8

The concentration of H+ from ionization is equal to the [OH–] from water,

[H+]H2​O=[OH–]H2​O

=x (say)

[H+]total=1.0×10−8+x

But

[H+][OH–]=1.0×10−14

(1.0×10−8+x)(x)=1.0×10−14

X2+10−8x–10−14=0

Solving for x, we get x=9.5×10−8

Therefore,

[H+]=1.0×10−8+9.5×10−8

=10.5×10−8

=1.05×10−7

pH=–log[H+]=–log(1.05×10−7)=6.98

Hence, this is the answer