What is the pH of an aqueous solution with a hydroxide ion concentration of 1.2 x 10–6 M?
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Answer:
Given :-[OH-] = 1.2•10^-6
pOH = -log[OH-]
= -log [1.2•10^-6]
= 6 - log 1.2
= 6 - 0.079
pOH = 5.92
pH = 14 - pOH
= 14 - 5.92
pH = 8.08
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