What is the pH of pure water at one hundred degrees Celsius? 1. 5 2. 6 3. 7 4. 8
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Kw of water = [H+][OH-]
10^-12 = [H ][OH ] at 100°C
Let us assume the concentration of H+ = x
Since each water molecules dissociates into one proton and one hydroxide ion.
i.e. the quantity or the concentration of these two ions will be equal in water.
[H+] = [OH-] Therefore
10^-12 = x.x
10^-12= x^2
so x = 10^-6
[H ] = [OH ]= 10^-6
pH = - log [H+]= - log 10^-6
pH = 6 log10 = 6 (log10 = 1)
so 2nd is correct answer
i hope it will help you
regards
10^-12 = [H ][OH ] at 100°C
Let us assume the concentration of H+ = x
Since each water molecules dissociates into one proton and one hydroxide ion.
i.e. the quantity or the concentration of these two ions will be equal in water.
[H+] = [OH-] Therefore
10^-12 = x.x
10^-12= x^2
so x = 10^-6
[H ] = [OH ]= 10^-6
pH = - log [H+]= - log 10^-6
pH = 6 log10 = 6 (log10 = 1)
so 2nd is correct answer
i hope it will help you
regards
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