What is the ph of resulting solution when75 ml of 0.2m hcl and 50 ml of 0.1 m naoh mixed?
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Answer:
M1V1 - M2V2 =MV3
0.2×50–0.1×50=M(100)
M=[H+]=0.05
pH=-log[H+]
pH=-log(0.05)
pH=1.30103
Hope You Got It.
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