what is the ph of solutation made by mixing equal volumes of 0.1 NH2SO4, 0.1 N-HNO3,O.1N-HCL?
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Before neutralization.
Millimoles of HCl =50x0.4=20
Millimoles of NaOH= 50x0.2=10
After neutralization,
Millimoles of NaOH=0
Millimoles of HCl=10 (by the concept of limiting reagent)
HCl will get dissociated into H+ and Cl-
Now concentration of H+ = 10/100=0.1M (the solution becomes 100 ml)
SO by the formula
pH=-log[H+]
we will get pH= 1
Hope so it helped u..
If u are not satisfied u can surely comment , i'll try for more.
And put me in brainliest.
Millimoles of HCl =50x0.4=20
Millimoles of NaOH= 50x0.2=10
After neutralization,
Millimoles of NaOH=0
Millimoles of HCl=10 (by the concept of limiting reagent)
HCl will get dissociated into H+ and Cl-
Now concentration of H+ = 10/100=0.1M (the solution becomes 100 ml)
SO by the formula
pH=-log[H+]
we will get pH= 1
Hope so it helped u..
If u are not satisfied u can surely comment , i'll try for more.
And put me in brainliest.
medhavmule:
Please mark me as brainliest
well done friends.you do not no how you help me.thanks.
can you also teell me the answer of the question?
ques-the concentration of acetate ions in 1M acetic acid solution containing 0.1 M HCL is? (Ka= 2/1000000 )
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