What is the pH of the resulting solution when equal volumes of 0.1M NaOH and 0.01M HCl are mixed
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12.65
when equal volumes of acid and bases are mixed then resulting solution alkaline if the concentrartion of base is taken high
n1v1-n2v2= NV
0.1*1 - 0.01*1 = N*2
N=0.09/2 = 0.045
[OH-] = 0.045N
pOH= -log(0.045) = 1.35
pH = 14-pOH
pH= 14-1.35 = 12.65
when equal volumes of acid and bases are mixed then resulting solution alkaline if the concentrartion of base is taken high
n1v1-n2v2= NV
0.1*1 - 0.01*1 = N*2
N=0.09/2 = 0.045
[OH-] = 0.045N
pOH= -log(0.045) = 1.35
pH = 14-pOH
pH= 14-1.35 = 12.65
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