Question

What is the pH of the solution containing 100 mg of NaOH in 250 mL of water?

Answer 1

Explanation:

100 mg in water = NaOH

250 + 100 = solution

$\frac{mass \: of \: solute \: }{volume\: of \: solution} \times 100$

$\frac{100}{350} \times 100$

$\frac{1000}{35}$

$= 28.5$

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Answer 2

Answer:

hlo dear

Explanation:

Explanation:

100 mg in water = NaOH

250 + 100 = solution

\frac{mass \: of \: solute \: }{volume\: of \: solution} \times 100

volumeofsolution

massofsolute

×100

\frac{100}{350} \times 100

350

100

×100

\frac{1000}{35}

35

1000

= 28.5=28.5

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