What is the ph solution of 0.36M HCL
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❣❣heya!❣❣
[H^+] = a × Molarity
= 1 × 0.35 M
= 0.35 M (the concentration of H^+)
pH = - log [H^+]
= - log 3.5×10^-1
= 1 - log 3.5
= 0.456
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