what is the ph value of 25ml, 0.1M HCl + 25.1ml, 0.1M NaOH
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Number of millimoles of NaoH=25×0.1=2.5
Millimoles of HCL=25×0.08=2 Now 2 Millimoles of Hcl will neutralize 2
millimoles of NaoH=Molarity of OH
ions=0.51500=10^(3)
poH=3 Or, pH =14-3=11
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