Question

What is the ploidy of oospore, coleoptile, and aleurone layer cells developed from the hexaploid female and diploid male parents?

Answer 1

Explanation:

the given ploidy of female is 6n then, 6n/2=3n

the given ploidy of male is 2n then, 2n/2=n

hence two male gamets will fused with egg so,2n

then total ploidy when fertilisation occur is 5n

• the ploidy of oospore is "n"
• ploidy of Coleoptile is "2n"
• ploidy of aleurone layer is "3n"

hope this may help you

Answer 2

the ploidy of oospore is n, Coleoptile is 2n and aleurone layer is 3n

Explanation:

• the ploidy of the female is equal to 6n. Hence the ploidy of the aleurone layer will be half of these that is will be equal to 3n since it is found in the gamut of the female. The ploidy of the oospore will be equal to n.

• The two will fuse and the ploidy of the the offspring will be equal to 2n  + 3n = 5 n

• this is because too of the male gamete will fuse with the egg to form the offspring.

To know more about ploidy of cells,

If female plant is tetraploid and male plant is hexaploid then what

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