Chemistry, asked by shazz2632, 4 hours ago

What is the poh of 0.02 M Ca(OH)2

Answers

Answered by amitkumarswain2005

0

pOH = -log 10 [HO-]

[HO-] = 0.04×mol×L^(-1)

pOH = - log 10 (0.04) = -(-1.40) = 1.40

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