Question

What is the poh of a 2.70x10-11 m solution of litum hydroxide (lioh)?

Answer 1

The p O H of a solution is defined in terms of the concentration of hydroxide ions in solution as follows:

p O H = − log [ O H − ] .

In this question,

[ O H − ] = 8.4 × 10 − 11 M , thus the p O H can be calculated by:

p O H = − log ( 8.4 × 10 − 11 ) = 10.0757 ≅ 10.08

So the pOH of the solution would be: 10.08