What is the poh of a solution that has a oh- concentration equal to?
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Sandy,
Remember the formula:
POH = -log [OHA]
We are given the concentration of OH-
pOH = - log (9.7 x 10-11)
pOH = - (-10.)
pOH = 10.
Hope this helps!
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Explanation:
where [OH−] is the hydroxide ion concentration of the solution in M or mol⋅dm−3 , moles per cubic decimeter, or equivalently moles per liter. Substituting [OH−]=1.36⋅10−10 mol⋅dm−3 , pOH=9.866 .
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