What is the point of intersection of a line parallel to the Y axis at a distance of 5 units to the left of it with the X axis?
Answers
Given : the point of intersection of a line parallel to the Y-axis at a distance of 5 units to the left of it with the X-axis
To Find : point of intersection
Solution:
Y-axis Equation is x = 0
Line parallel to y axis is x = c
at a distance of 5 units
Hence c = ± 5
=> x = ±5
left of Y axis is - ve and Right is + ve
Hence x = - 5
x axis is y = 0
Hence intersection point is ( -5 , 0 )
point of intersection of a line parallel to the Y-axis at a distance of 5 units to the left of it with the X-axis is ( -5 , 0 )
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Answer:
Step-by-step explanation:
(-5,