Question

what is the point of intersection of the lines y=3x+6 and y+3x=0

Answer 1

Step-by-step explanation:

first equation = (y = 3x+6)

second = (y= -3x)

if L.H.S is equal than R.H.S should also be equal

3x+6= -3x

3x+3x = -6

x= -1

Answer 2

Answer:

(-1, 3)

Step-by-step explanation:

→ y = 3x + 6 ........(1)

→ y + 3x = 0

→ y = -3x

Substitute value of y in (1)

→ -3x = 3x = 6

→ -3x - 3x = 6

→ -6x = 6

Divide by 6 on both sides

→ -6x/6 = 6/6

→ x = -1

Substitute value of x in y

→ y = -3(-1)

→ y = 3

Hence, the point of intersection of the lines y=3x+6 and y+3x=0 is (-1, 3).