Question

What is the point on graph of equation 2x+5y=20 whose x coordinate is 5/2 times of its ordinate

Answer 1

(5,2)

Step-by-step explanation:

Ordinate = y

Absscisa = 5y/2

Putting 'x' value in equation

2x + 5y = 20

2(5y/2) + 5y =20

5y + 5y = 20

10y = 20

y = 20/10

y = 2

substituting the value in Absscisa & Ordinate:-

Ordinate = y = 2

Absscisa = 5y/2 = 10/2 = 5

therefore the coordinate is (5,2)

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