Question

What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?
y minus (negative 3) = negative 4 (x minus 1)
y minus 1 = negative 4 left-bracket x minus (negative 3) right-bracket
Negative 1 minus y 1 = negative 4 (negative 3 minus x 1)
3 minus y 1 = negative 4 (1 minus x 1)

Answer 1

Answer: D

Step-by-step explanation: hope this helps

Answer 2

Correct Question

What is the point-slope form of a line that has a slope of –4 and passes through point    (–3, 1)?

Answer:

The point-slope form of a line that has a slope of –4 and passes through point (–3, 1) is $y =-4x -11$.

Step-by-step explanation:

Given:

A line that has a slope of –4.

Line passes through point (–3, 1).

To Find:

The point-slope form of a line.

Formula Used:

The point-slope  equation of line passing through point $(x_{1,} y_{1})$ whose

whose slope is m.

$(y - y_{1} ) = m (x - x_{1} )$    ------------ formula no.01.

Solution:

As given,a line that has a slope of –4.

$m=-4$

As given,line passes through point (–3, 1).

$(x_{1,} y_{1})=( -3,1)$

Applying formula no.01.

$(y - 1) = (-4) (x - (-3) )$

$(y - 1) = (-4) (x +3 )$

$y-1=-4x-12$

$y =-4x-11$

Thus, the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)  is $y =-4x -11$.

#SPJ3