What is the point-slope form of the line tangent to the curve y = (4x + 2)^2at the point (-1,4)?
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Answer:
this is your answer
Step-by-step explanation:
Putting y=x in y=
4−x
2
, we get x=
2
,−
2
.
So, the point is (
2
,
2
).
Differentiating y
2
+x
2
=4 w.r.t. x,2y
dx
dy
+2x=0 or
dx
dy
=−
y
x
⇒at(
2
,
2
),
dx
dy
=−1
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