Math, asked by neerulect49, 1 month ago

What is the point-slope form of the line tangent to the curve y = (4x + 2)^2at the point (-1,4)? ​

Answers

Answered by alkasurin37
0

Answer:

this is your answer

Step-by-step explanation:

Putting y=x in y=

4−x

2

, we get x=

2

,−

2

.

So, the point is (

2

,

2

).

Differentiating y

2

+x

2

=4 w.r.t. x,2y

dx

dy

+2x=0 or

dx

dy

=−

y

x

⇒at(

2

,

2

),

dx

dy

=−1

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