what is the point to make it congruent and how
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AC=AB (given)
AD=AD (common)
DC=DB (given that AD bisects BC)
so, ∆ACD is congruent to ∆ BAD .
PLZ MARK BRAINLIEST
AC=AB (given)
AD=AD (common)
DC=DB (given that AD bisects BC)
so, ∆ACD is congruent to ∆ BAD .
PLZ MARK BRAINLIEST
sachin271:
it is not given that it is a bisector
it is to proove
okk thanku
i am also becoz i have to write to proof in pic in front of ad bisects bc, so i also feel sorry to you
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