What is the polar form of 1?
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Polar form of 1 is (cis 0)
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4
1
=1+0i
So,tan theta=0
Therefore theta =0
r=root over 1^2+0^2
=1
Polar form =r(cos theta+isin theta)
=1(1+0)
=1
=1+0i
So,tan theta=0
Therefore theta =0
r=root over 1^2+0^2
=1
Polar form =r(cos theta+isin theta)
=1(1+0)
=1
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