What is the polynomial of the smallest degree with integer coefficients and with zero's 3,1+i,-1?
Answers
Chapter - Polynomials
Question. What is the polynomial of the smallest degree with integer coefficients and with zeroes 3, 1 + i, 1 - i ?
Solution.
We know that, if a, b, c be the zeroes of a polynomial, then the polynomial be
p(x) = (x - a) (x - b) (x - c)
Using the above formula, we get the required polynomial
p(x) = (x - 3) {x - (1 + i)} {x - (1 - i)}
= (x - 3) {x² - (1 + i + 1 - i) x + (1^2 - i^2)}
= (x - 3) {x² - 2x + (1 + 1)}
= (x - 3) (x² - 2x + 2)
= x³ - 2x² + 2x - 3x² + 6x - 6
= x³ - 5x² + 8x - 6
This is the required polynomial.
Answer. Required polynomial = x³ - 5x² + 8x - 6.
Answer :
Root = 3, 1+i, -1
Therefore, We know that no real roots always exist in pairs.
So, one more root will be 1 -i
Therefore, sum of root = 4
And product of the root = 3(-1) (1+1) (1-i)
= -3 (1- )
= -3 (2)
= -6
Hope this will help you.