Question

What is the position isomers of C4H10O

Answer 1

Answer:

See below.

Explanation:

We know from the formula that these isomers contain no rings or double bonds.

The isomers must be alcohols and ethers.

Let's start by drawing the alcohols.

Start with four carbons in a row and put an OHgroup in every possible position.

This gives us

1. CH3CH2CH2CH2OH, butan 1-ol

and

2. CH3CH2CH(OH)CH3, butan-2-ol

Now use a 3-carbon chain with a CH3 on the middle carbon.

This gives

(CH3)2CHCH2OH, 2-methylpropan-1-ol

and

(CH3)3COH, 2-methylpropan-2-ol.

Now for the ethers.

Let's start with five atoms in a row.

This gives

CH3CH2CH2OCH3, 1-methoxypropane

and

CH3CH2OCH2CH3, ethoxyethane

Finally, the only choice for a branched-chain ether is

(CH3)2CHOCH3, 2-methoxpropane.

And there are your seven isomers of C4H10O.