What is the position of 999 in the sequence represented by they nth term n^3 -1
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Step-by-step explanation:
sequence is
(1³-1), (2³-1). ,(3³-1)..............,.(10³-1)
0, 7 , 26,....................999
______________________________
since, n³-1= 999
=> n³ = 999+1= 1000
=> n³= 10³
comparing the exponent.,
n=10
therefore 999 is the 10nth term of sequence
Answer = 10nth term
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