Question

what is the position of image when object is placed at a distance of 10 cm from a convex lens of focal length 10 centimetre​

Answer 1

Since, 1/f= 1/v-1/u

=> 1/10= 1/v-1/10

=> 1/10+1/10= 1/v

=> 2/10= 1/v

=> 1/5=1/v

Therefore, image is located at a distance of 5cm from the convex lens.....

Answer 2

Answer:

This is a Magnifying Glass, so expect erect enlarged virtual image.

Using Real Is Positive convention u=10 and f=20

1/u + 1/v = 1/f

1/v = 1/f - 1/u = 1/20 - 1/10 = -1/20

v = -20 (virtual, erect) and twice the size

i hope it's helpful 4 u

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