Question

what is the position of the image when
on object is placed at a distance of 30 cm from a
length 30 cm?
Concave mirror of focal​

Answer 1

ANSWER

Concave lens produce a virtual erect diminished image

By using len's formula, By consention μ=30 & F=−30

μ

1

+

v

1

=

f

1

⇒

30

1

+

v

1

=−

30

1

⇒

v

1

=−

30

1

−

30

1

⇒

v

1

=−

15

1

v

1

=−0.066

So image is erect, virtual, 15cm from the lens (between lens & object)