Physics, asked by mganushkao4o, 1 year ago

What is the positive and negative charge on 18 cc of water ?

Answers

Answered by tannoypathak
3

Amount of water = 18cc = 18mL [ 1cc = 1mL ]

we know, density of water = 1 g/mL

so, mass of given amount of water = density × volume = 18mL × 1 g/mL = 18g

we also know, Molecular weight of water , H₂O = 18g/mol

so, number of moles of water = weight/Molecular weight = 18/18 = 1 mol

In water , H₂O there are 10 electrons [ 2 of Hydrogen atoms and 8 of oxygen atom ]

so, number of moles of electrons in 1 mole of water = 10 × 1 = 10

now, number of electrons = number of moles × Avogadro's number

= 10 × 6.023 × 10²³ = 6.023 × 10²⁴

We know, charge on an electron = 1.6 × 10⁻¹⁹ C

so, charge on 6.023 × 10²⁴ electrons = 6.023 × 10²⁴ × 1.6 × 10⁻¹⁹ C

= 9.632 × 10⁵ C

Because you know water is neutral molecule , it means positive charge and negative charge will be same amount .

Hence, positive charge = 9.632 × 10⁵C

negative charge = -9.632 × 10⁵C

I hope it will help you


mganushkao4o: so well explained thank you so much
tannoypathak: welcome bro
Answered by Anonymous
7

Your question

What is the positive and negative charge on 18 cc of water?

Your answer

Given

  • amount of water = 18 cc = 18 mL
  • ( as 1 cc = 1 mL )

Focusing on the given molecule ,

i.e Water ( H2O )

We know that ,

  • Total no. of electrons present in water = 10
  • i. e. 2 hydrogen atom contains = 2 electrons and 1 oxygen atom contains = 8 electrons

So there are 10 electrons.

Now,

For No. of moles of water of water ,

  • Weight / Mass of the given water = Density x volume
  • As the density of the water = 1 g/mL and the volume of the water is = 18 mL
  • Weight = 1 x 18 = 18 grams

  • Molecular weight of water (H2O) = 18 g/mol

  • So , now we can easily calculate the moles of water as we have both the original weight and molecular weight of water.

  • No. of moles of water = Weight of water / Molecular weight of water
  • = 18 / 18 = 1 mol

As the water have 10 electrons ,

  • so no. of moles of electrons in 1 mole of water molecule = 10 x 1 = 10

Now , 1 mol of water contains electrons

  • = no. of moles of electrons x Avogadro's number
  • = 10 x 6.023 x 10²³
  • = 6.023 x 10²⁴

So we have 6.023 x 10²⁴ electrons in 1 mol of water.

Now , we can easily calculate the charge on 1 mole of water or 6.023 x 10²⁴ electrons by multiply it with the official charge on an electron.

i.e

  • Total charge on electrons in given water molecule = electron's no. x charge on an electron
  • = 6.023 x 10²⁴ x ( - 1.6 x 10^-19 ) C
  • = - 9.632 x 10^5 C

And same for the total charge involves protons

  • Because water is a stable molecule and the no. of electrons and protons are equal also the charge on an electron and proton is equal So ,

  • Charge ( Protons ) = 9.632 x 10^5 C

So the total / net Charge on water molecule

  • = 9.632 x 10^5 C + ( -9.632 x 10^5 C )
  • = 0 (zero)
  • i. e stability / neutrality of Water / H2O molecule

And for this question

  • The positive charge present = 9.632 x 10^5 C
  • The negative charge present = -9.632 x 10 ^5 C
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