Question

what is the potential at a point which is at a distance of 9 cm from point charge 1nC​

Answer 1

Answer:

Given : r=9 cm =0.09 m

Charge Q=3 nC =3×10

−9

C

Potential at a distance 9 cm, V=

r

kQ

where k=9×10

9

∴ V=

0.09

9×10

9

×3×10

−9

=300 V