What is the potential difference between the ends of a conductor of 16 ohm resistance, when a current of 2A flows through it
Answers
Answered by
0
Answer:
GIVEN:
R=16Ω
I= 2Ampere
potential difference (v) =?
Explanation:
v=i×R
so, v=2×16
=32volts(or) 32v
you may also easily extract the above formula by using this picture
Attachments:
Similar questions