Question

what is the potential difference between the ends of a conductor of 16 ohm resistance when a current of 1.5 ampere flows through it​

Answer 1

Answer:

R= v i

6=V/1.5

V=1.5×6 if we remove point then comes zero

V=24.0Explanation:

Answer 2

Answer:

The potential difference will be 24 volts between the ends of the conductor.

Explanation:

Given resistance of the conductor , $R=16$Ω

The current flows through the wire $I=1.5A$

From Ohm's law ,

          ∴      $V=IR\\ V=(1.5A)(16ohm) \\ V=24volt$                      [∵  1AΩ = 1 volt]

Therefore the potential difference will be 24volts if resistance is 16Ω and current 1.5A.