Question

what is the potential difference between the terminals of a battery if 250 joules of work is required to transfer 20 columns of charge from one terminal of battery to the other

Answer 1

Answer:

Potential Difference $\longrightarrow$ 12.5

Explanation:

Given:

Work Done $\longrightarrow$ 250J

Charge $\longrightarrow$ 20C

To Find:

Potential Difference, i.e, Voltage.

Solution:

We know that,

$\sf Volt = \dfrac{Workdone}{Charge}$

Now, we substitute the given values in the equation above.

$\sf V = \dfrac{250}{20}$

'0' gets cancelled,

$\sf V = \dfrac{25}{2}$

V = 12.5

Hence the Potential difference flowing between the terminals of a battery when 250J of work is done to move a charge of 20C is 12.5V.

Answer 2

Given, W = 250 J

  ⁣   ⁣ Q = 20 C

We know, V = W / Q

  ⁣   ⁣    ⁣V = 250 / 20

  ⁣   ⁣   ⁣   = 12.5 V ...✔