Question

what is the potential difference between two points if 250joules of work is done in moving charge of 20​

Answer 1

Answer : 12.5 volts

$\rule{100}2$

Explanation :

It is given that,

• Work done = 250 j
• charge = 20 coulomb

We've to find the potential difference ( v ).

We know that,

Potential difference ( v ) = work done/charge

Substitute the values in the given formula.

we get,

➜ v = 250/20

➜ v = 12.5 volts

Hence,

The potential difference b/w two points is 12.5 volts.

$\rule{200}2$

Answer 2

$\huge\boxed{\fcolorbox{yellow}{pink}{Answer :- }}$

Gɪᴠᴇɴ ,

ᴡ = 250 ᴊᴏᴜʟᴇs.

ǫ = 20 Cᴏᴜʟᴏᴍʙ.

ᴀs ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ...

Pᴏᴛᴇɴᴛɪᴀʟ ᴅɪғғᴇʀᴇɴᴄᴇ , ᴠ = ᴡ/ǫ

ᴠ = 250 / 20

$\huge\boxed{\fcolorbox{blue}{purple}{ v = 12.5}}$