Question

What is the potential due to a short dipole
moment 4.5× 10^-10C-m at a distance 1m from it, (i)
on its axis (ii) on its perpendicular bisector?
A) 0, 0
B) 0, 4.05 V
C) 4.05 V, 0
D) 4.05 V, 2.025 V

Answer 1

Explanation:

The potential of a dipole is given by,

P=

r

2

kpcosθ

For a point in the direction of dipole on the axis θ=0

P

axis

=kp/r

2

=9×10

9

×4.5×10

−10

=4.05V

For a point in the axis perpendicular to dipole θ=90

P

perpendicular

=0V