Question

What is the potential dueto a charge of 5*10^-7C located 10 cm away

Answer 1

Answer:

Potential 'V' due to a point charge 'q' is given as

$V = \frac{kQ}{r}$

taken referance as V(∞) = 0

k = 9 x 10⁹ Nm²/C²

Q = 5 x 10⁻⁷ C

r = 0.1m

V = 9 x 10⁹ x 5 x 10⁻⁷ / 0.1 = 45000 V = 45kV