Question

what is the potential energy of a 2kg plant that is on a windowsill 1.3 m high

Answer 1

Answer:

P.E = 25.48 Joule

Explanation:

Here,

mass (m) = 2kg

height (h) = 1.3m

g = 9.8m/s^2

P.E = mgh

= (2) (9.8) (1.3)

P.E = 25.48 Joule

Thus, the potential energy of a 2kg plant that is on a windowsill 1.3m high is 25.48 Joule

Answer 2

Answer:

The potential energy of a 2kg plant that is on a windowsill 1.3 m high is 25.48$J$

Explanation:

The energy obtained by the object due to its position or its strain is called potential energy. Here it is given that,

mass of the plant = 2$kg$

Height of the windowsill = 1.3$m$

we know that, acceleration due to gravity = 9.8$m/s^{2}$

The equation to find potential energy = U = m×g×h

where m= mass of the object, g = acceleration due to gravity, h = height

Therefore,

            U = 2×9.8×1.3

                = 25.48 $J$

The potential energy of a 2kg plant that is on a windowsill 1.3 m high is 25.48$J$