What is the potential of a cell containing two hydrogen electrodes in which the anode is in contact with 10(Power negative 5) M Hcland the cathode is in contact with 1000 times the concentration of Hcl as anode? Please help! URGENT!
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Answered by
41
in this cathode and anode boh aare hydrogen electrode
[H^+] in cathode = 10 (power ngative 2 ) as the con of HCl is 1000 timess greater than that of anode and [H^+] at anode is 10 (power negative 5 )
E^0 cell = 0 as cathode and anode are htdrogen , therefore
EMF of cell = 0.059 / 1 log 10^-2 / 10^ -5 = 0.059 x 3 =0.177V.
[H^+] in cathode = 10 (power ngative 2 ) as the con of HCl is 1000 timess greater than that of anode and [H^+] at anode is 10 (power negative 5 )
E^0 cell = 0 as cathode and anode are htdrogen , therefore
EMF of cell = 0.059 / 1 log 10^-2 / 10^ -5 = 0.059 x 3 =0.177V.
Answered by
23
Answer:
The answer is 0.18
Explanation:
Using emf formulae
E(cell) = E* + 0.0591/n log [cathode electrolyte]/[anode electrolyte]
where [.....] denote the concentration respectively
now given hydrogen cell and for a hydrogen cell E*=0
since HCl is the electrolyte no of ions is 1 n=1
E = 0 + 0.0591 log10^3
= 0.0591(3)
= 0.18
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