Question

What is the potiantial drop across a cell of 30 volt having internal resistance 1 ohm and the current of 3 ampare is following in the circuit

Answer 1

Answer:

Refer image .1

Given :- Let the current How in 3Ω is i, and 6Ω is i

1

=1ampere

i

1

+i

2

=I

V

A

−V

B

=i

1

×3Ω=i

2

×6

⇒1×3=i

2

×6

2

i

=

2

1

ampere

Hence I=i

1

+i

2

=1+0.5=1.5ampere

Req=2+

3+6

3×6

=2+

9

3×6

=4Ω

equivalent circuit

Refer image .2

From KVL

1req=v

v=1.5×4

=6volt