what is the power developed by the engines of a jetliner which gives a thrust of 3.6*10^5 N at 1000 km/h ? plz solve this question it is very urgent .
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Answered by
26
v ( speed )= 1000km/h =
thrust ( f ) = 3.6 * 10^5 N
P = f * v
= 3.6 * 10^5 * [tex] \frac{5}{18} * 1000 Nm/s [/tex]
= 10^8 Nm/s
= 10^8 W ( answer )
thrust ( f ) = 3.6 * 10^5 N
P = f * v
= 3.6 * 10^5 * [tex] \frac{5}{18} * 1000 Nm/s [/tex]
= 10^8 Nm/s
= 10^8 W ( answer )
Anonymous:
good ans
Answered by
18
thrust = 3.6 * 10^5
speed = 5/18 * 1000 m/s = 2500/9
power = thrust * speed
= 3.6 * 0^5 * 2500/9
= 100000000 j/s
= 10^8 w
speed = 5/18 * 1000 m/s = 2500/9
power = thrust * speed
= 3.6 * 0^5 * 2500/9
= 100000000 j/s
= 10^8 w
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